A model rocket is launched with an initial upward velocity of 204 ft/s. The rocket's height h (in feet) after t seconds is given by the following.REST ATTACHED BELOW!!!!!!! HELP ME!!!!! Quickly!!!!!!!!!!

Answer:Step-by-step explanation:h(t) represents the height of the rocket at certain times during its travel.  If we are looking for the times when the rocket is 100 feet in the air, we sub in 100 for h(t) and solve for t by factoring.[tex]100 =-16t^2+204t[/tex] We will set this equal to zero by moving everything on to the same side and factoring however you like:[tex]-16t^2+204t-100=0[/tex]Solving for t and you have the values oft = .51 seconds andt = 12.24 secondsThere are 2 times because, first and foremost, this is a quadratic (second degree) and secondly, when we throw something up into the air, it reaches it max height, then begins to fall back to earth due to the pull of gravity and it will pass coming down everything it passed going up, just at a few seconds later.