C. ax + bx = 10I need help, I am going into HS and don't understand how to solve this. This is summer HW

Answer:[tex]x=\frac{10}{a+b}[/tex] with [tex]a \neq -b[/tex].Step-by-step explanation:So we have:[tex]ax+bx=10[/tex] and we are solving for [tex]x[/tex].We want to get all terms that have x on one side and all terms without x on the opposing side.  This is actually already done.Now we are going to factor the side that has the x's.  We are going to factor x out.[tex]x(a+b)=10[/tex]Now you have a number times x and you want x by itself. The inverse operation of multiplication is division. So we are going to divide both sides by [tex](a+b)[/tex]:[tex]x=\frac{10}{a+b}[/tex]You could probably stop here but just in case....[tex]a+b[/tex] can't be 0 because then you would have 10/0 which is not a number.So if we solve [tex]a+b=0[/tex] we can find out what we don't want and b to be:[tex]a+b=0[/tex]Subtract b on both sides:[tex]a=-b[/tex]So we we don't want [tex]a[/tex] and [tex]-b[/tex] to be the same value.