Solve the system of equations: y= 3x y= x^2 - 4 A. (-1, -3) and (4, 12) B.(-2, 0) and (2,0) C.(-1,3) and (4,5) D. (-2,-6) and (2,6)

Answer: A. (-1,-3) and (4,12) Step-by-step explanation: Make both equations equal to each other and solve for the variable x: [tex]y=y\\3x=x^2-4\\x^2-3x-4=0\\[/tex] Factor the expression. Find two numbers that when you add them you get -3 and the product of both numbers be -4. These numbers are 1 and -4. Then: [tex](x+1)(x-4)=0\\\\x+1=0\\x=-1\\\\x-4=0\\x=4[/tex] Substitute these values into one the original equations and solve for y: [tex]y=3(-1)\\y=-3\\\\y=3(4)\\y=12[/tex] Therefore, you get that the solution is: (-1,-3) and (4,12)