Two dogs, Rufus and Daisy, are eating dinner. The amount of food (measured in grams) and Rufus's bowl after t minutes is R(t) = 450-150t, and the amount of food (measured in grams) in Daisy's bowl after t minutes is D(t)= 400 - 120t. Express the ratio of the amount remaining in Daisy's bowl to the amount remaining in Rufus's bowl as a rational function, and simplify.
Accepted Solution
A:
Answer:A.Step-by-step explanation:So we want the ratio of the food amount in Daisy's bowl (D) to the food amount in Rufus's bowl (R) at time t.So we are asked to do:[tex]\frac{D}{R}[/tex][tex]\frac{400-120t}{450-150t}[/tex]Let's see if we can simplify any.Every single term on top and bottom have a common factor of 10 since they each contain a factor that ends in 0. I'm going to divide top and bottom by 10:[tex]\frac{40-12t}{45-15t}[/tex]The answer is A.I can see no more common factors between 40,12t,45, and 15t:40=2(2)(2)(5)12t=2(2)(3)t45=3(3)(5)15t=3(5)tThey don't all contain a common factor when looked at altogether.