A weighted die, numbered one through six, has a probability of 1/4 of rolling a six. if this die is rolled three times, and each roll is independent, what is the probability of rolling at least two sixes?
Accepted Solution
A:
Probability of rolling no sixes = (3/4)^3 = 27/64
Probability of first one being 6 and the rest Not 6 = 1/4 * 3/4* 3/4 = 9/64
THere are 3 ways for this to happen so total probability of 1 six = 27/64
Therefore Probability of 2 or more sixes = 1 - 2(27/64) = 10/54 = 5/27