Q:

square root of 2 divided by the cube root of 2

Accepted Solution

A:
Answer: [tex]\sqrt[6]{2}[/tex]Step-by-step explanation: You know that the expression is [tex]\frac{\sqrt{2}}{\sqrt[3]{2}}[/tex] By definition we know that: [tex]\sqrt[n]{a}=a^{\frac{1}{n}[/tex] You also need to remember the Quotient of powers property: [tex]\frac{a^n}{a^m}=a^{(n-m)}[/tex] Therefore, you can rewrite the expression: [tex]=\frac{2^{\frac{1}{2}}}{2^{\frac{1}{3}}}[/tex] Finally, you have to simplify the expression. Therefore, you get: [tex]=2^{(\frac{1}{2}-\frac{1}{3})}\\=2^{\frac{1}{6}}\\=\sqrt[6]{2}[/tex]